Integrand size = 22, antiderivative size = 65 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {8333293 x}{390625}+\frac {5555569 x^2}{156250}-\frac {422841 x^3}{15625}-\frac {1677159 x^4}{12500}-\frac {228447 x^5}{3125}+\frac {35883 x^6}{250}+\frac {34992 x^7}{175}+\frac {729 x^8}{10}+\frac {121 \log (3+5 x)}{1953125} \]
8333293/390625*x+5555569/156250*x^2-422841/15625*x^3-1677159/12500*x^4-228 447/3125*x^5+35883/250*x^6+34992/175*x^7+729/10*x^8+121/1953125*ln(3+5*x)
Time = 0.01 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {966660747+5833305100 x+9722245750 x^2-7399717500 x^3-36687853125 x^4-19989112500 x^5+39247031250 x^6+54675000000 x^7+19933593750 x^8+16940 \log (3+5 x)}{273437500} \]
(966660747 + 5833305100*x + 9722245750*x^2 - 7399717500*x^3 - 36687853125* x^4 - 19989112500*x^5 + 39247031250*x^6 + 54675000000*x^7 + 19933593750*x^ 8 + 16940*Log[3 + 5*x])/273437500
Time = 0.19 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {(1-2 x)^2 (3 x+2)^6}{5 x+3} \, dx\) |
| \(\Big \downarrow \) 99 |
| \(\displaystyle \int \left (\frac {2916 x^7}{5}+\frac {34992 x^6}{25}+\frac {107649 x^5}{125}-\frac {228447 x^4}{625}-\frac {1677159 x^3}{3125}-\frac {1268523 x^2}{15625}+\frac {5555569 x}{78125}+\frac {121}{390625 (5 x+3)}+\frac {8333293}{390625}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle \frac {729 x^8}{10}+\frac {34992 x^7}{175}+\frac {35883 x^6}{250}-\frac {228447 x^5}{3125}-\frac {1677159 x^4}{12500}-\frac {422841 x^3}{15625}+\frac {5555569 x^2}{156250}+\frac {8333293 x}{390625}+\frac {121 \log (5 x+3)}{1953125}\) |
(8333293*x)/390625 + (5555569*x^2)/156250 - (422841*x^3)/15625 - (1677159* x^4)/12500 - (228447*x^5)/3125 + (35883*x^6)/250 + (34992*x^7)/175 + (729* x^8)/10 + (121*Log[3 + 5*x])/1953125
3.13.90.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Time = 0.80 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.71
| method | result | size |
| parallelrisch | \(\frac {729 x^{8}}{10}+\frac {34992 x^{7}}{175}+\frac {35883 x^{6}}{250}-\frac {228447 x^{5}}{3125}-\frac {1677159 x^{4}}{12500}-\frac {422841 x^{3}}{15625}+\frac {5555569 x^{2}}{156250}+\frac {8333293 x}{390625}+\frac {121 \ln \left (x +\frac {3}{5}\right )}{1953125}\) | \(46\) |
| default | \(\frac {8333293 x}{390625}+\frac {5555569 x^{2}}{156250}-\frac {422841 x^{3}}{15625}-\frac {1677159 x^{4}}{12500}-\frac {228447 x^{5}}{3125}+\frac {35883 x^{6}}{250}+\frac {34992 x^{7}}{175}+\frac {729 x^{8}}{10}+\frac {121 \ln \left (3+5 x \right )}{1953125}\) | \(48\) |
| norman | \(\frac {8333293 x}{390625}+\frac {5555569 x^{2}}{156250}-\frac {422841 x^{3}}{15625}-\frac {1677159 x^{4}}{12500}-\frac {228447 x^{5}}{3125}+\frac {35883 x^{6}}{250}+\frac {34992 x^{7}}{175}+\frac {729 x^{8}}{10}+\frac {121 \ln \left (3+5 x \right )}{1953125}\) | \(48\) |
| risch | \(\frac {8333293 x}{390625}+\frac {5555569 x^{2}}{156250}-\frac {422841 x^{3}}{15625}-\frac {1677159 x^{4}}{12500}-\frac {228447 x^{5}}{3125}+\frac {35883 x^{6}}{250}+\frac {34992 x^{7}}{175}+\frac {729 x^{8}}{10}+\frac {121 \ln \left (3+5 x \right )}{1953125}\) | \(48\) |
| meijerg | \(\frac {121 \ln \left (1+\frac {5 x}{3}\right )}{1953125}+64 x -\frac {56 x \left (-5 x +6\right )}{25}-\frac {1512 x \left (\frac {100}{9} x^{2}-10 x +12\right )}{125}+\frac {1701 x \left (-\frac {625}{9} x^{3}+\frac {500}{9} x^{2}-50 x +60\right )}{625}+\frac {5103 x \left (\frac {2500}{27} x^{4}-\frac {625}{9} x^{3}+\frac {500}{9} x^{2}-50 x +60\right )}{15625}-\frac {19683 x \left (-\frac {218750}{243} x^{5}+\frac {17500}{27} x^{4}-\frac {4375}{9} x^{3}+\frac {3500}{9} x^{2}-350 x +420\right )}{62500}+\frac {531441 x \left (\frac {625000}{243} x^{6}-\frac {437500}{243} x^{5}+\frac {35000}{27} x^{4}-\frac {8750}{9} x^{3}+\frac {7000}{9} x^{2}-700 x +840\right )}{5468750}-\frac {177147 x \left (-\frac {2734375}{243} x^{7}+\frac {625000}{81} x^{6}-\frac {437500}{81} x^{5}+\frac {35000}{9} x^{4}-\frac {8750}{3} x^{3}+\frac {7000}{3} x^{2}-2100 x +2520\right )}{27343750}\) | \(174\) |
729/10*x^8+34992/175*x^7+35883/250*x^6-228447/3125*x^5-1677159/12500*x^4-4 22841/15625*x^3+5555569/156250*x^2+8333293/390625*x+121/1953125*ln(x+3/5)
Time = 0.22 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.72 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {729}{10} \, x^{8} + \frac {34992}{175} \, x^{7} + \frac {35883}{250} \, x^{6} - \frac {228447}{3125} \, x^{5} - \frac {1677159}{12500} \, x^{4} - \frac {422841}{15625} \, x^{3} + \frac {5555569}{156250} \, x^{2} + \frac {8333293}{390625} \, x + \frac {121}{1953125} \, \log \left (5 \, x + 3\right ) \]
729/10*x^8 + 34992/175*x^7 + 35883/250*x^6 - 228447/3125*x^5 - 1677159/125 00*x^4 - 422841/15625*x^3 + 5555569/156250*x^2 + 8333293/390625*x + 121/19 53125*log(5*x + 3)
Time = 0.05 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.94 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {729 x^{8}}{10} + \frac {34992 x^{7}}{175} + \frac {35883 x^{6}}{250} - \frac {228447 x^{5}}{3125} - \frac {1677159 x^{4}}{12500} - \frac {422841 x^{3}}{15625} + \frac {5555569 x^{2}}{156250} + \frac {8333293 x}{390625} + \frac {121 \log {\left (5 x + 3 \right )}}{1953125} \]
729*x**8/10 + 34992*x**7/175 + 35883*x**6/250 - 228447*x**5/3125 - 1677159 *x**4/12500 - 422841*x**3/15625 + 5555569*x**2/156250 + 8333293*x/390625 + 121*log(5*x + 3)/1953125
Time = 0.20 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.72 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {729}{10} \, x^{8} + \frac {34992}{175} \, x^{7} + \frac {35883}{250} \, x^{6} - \frac {228447}{3125} \, x^{5} - \frac {1677159}{12500} \, x^{4} - \frac {422841}{15625} \, x^{3} + \frac {5555569}{156250} \, x^{2} + \frac {8333293}{390625} \, x + \frac {121}{1953125} \, \log \left (5 \, x + 3\right ) \]
729/10*x^8 + 34992/175*x^7 + 35883/250*x^6 - 228447/3125*x^5 - 1677159/125 00*x^4 - 422841/15625*x^3 + 5555569/156250*x^2 + 8333293/390625*x + 121/19 53125*log(5*x + 3)
Time = 0.29 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.74 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {729}{10} \, x^{8} + \frac {34992}{175} \, x^{7} + \frac {35883}{250} \, x^{6} - \frac {228447}{3125} \, x^{5} - \frac {1677159}{12500} \, x^{4} - \frac {422841}{15625} \, x^{3} + \frac {5555569}{156250} \, x^{2} + \frac {8333293}{390625} \, x + \frac {121}{1953125} \, \log \left ({\left | 5 \, x + 3 \right |}\right ) \]
729/10*x^8 + 34992/175*x^7 + 35883/250*x^6 - 228447/3125*x^5 - 1677159/125 00*x^4 - 422841/15625*x^3 + 5555569/156250*x^2 + 8333293/390625*x + 121/19 53125*log(abs(5*x + 3))
Time = 0.05 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.69 \[ \int \frac {(1-2 x)^2 (2+3 x)^6}{3+5 x} \, dx=\frac {8333293\,x}{390625}+\frac {121\,\ln \left (x+\frac {3}{5}\right )}{1953125}+\frac {5555569\,x^2}{156250}-\frac {422841\,x^3}{15625}-\frac {1677159\,x^4}{12500}-\frac {228447\,x^5}{3125}+\frac {35883\,x^6}{250}+\frac {34992\,x^7}{175}+\frac {729\,x^8}{10} \]